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ICE with /64 /opt

 
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mecej4



Joined: 31 Oct 2006
Posts: 1181

PostPosted: Fri Jul 05, 2019 4:05 pm    Post subject: ICE with /64 /opt Reply with quote

The following code, when compiled with /64 /opt, causes an internal compiler error. When the lines containing L1 are removed, the ICE does not occur.

Code:
      subroutine revprt()
      implicit none
      integer ia,ib,idx,j,kpagen

      character*170 crec
      logical*1  ::   l1
!
      kpagen = 0
      do idx = kpagen,1,-1
         do j = 1,42
            ia = 1 + 4*(j-1)
            ib = ia + 3
            crec(ia:ib) = '    '
         end do
         do ia = 168,1,-1
            if(crec(ia:ia) .ne. ' ') exit
         end do
         l1  = .false.
         do j = 14,1,-1
            if(crec(j:j) .ne. ' ' .and. .not.l1) l1 = .true.
            if(l1 .and. crec(j:j) .eq. ' ') exit
         end do
         kpagen = kpagen + 1
         if(idx .eq. 1) exit
      end do
      return
      end


P.S.: If the type of variable L1 is changed from LOGICAL*1 to just LOGICAL, the ICE goes away.


Last edited by mecej4 on Fri Jul 05, 2019 6:29 pm; edited 1 time in total
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PaulLaidler
Site Admin


Joined: 21 Feb 2005
Posts: 6002
Location: Salford, UK

PostPosted: Fri Jul 05, 2019 5:47 pm    Post subject: Reply with quote

Thank you for this bug report. I will make a note that it needs fixing.
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PaulLaidler
Site Admin


Joined: 21 Feb 2005
Posts: 6002
Location: Salford, UK

PostPosted: Mon Jul 08, 2019 7:47 am    Post subject: Reply with quote

This has now been fixed for the next release of FTN95.
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mecej4



Joined: 31 Oct 2006
Posts: 1181

PostPosted: Mon Jul 08, 2019 12:51 pm    Post subject: Reply with quote

Thank you for the prompt response.
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