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SIZE does not return 0 after DEALLOCATE

 
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simon



Joined: 05 Jul 2006
Posts: 268

PostPosted: Mon Apr 21, 2008 12:49 pm    Post subject: SIZE does not return 0 after DEALLOCATE Reply with quote

Why does the following program not indicate siez=0 in the third row of output? (The smiley face in line 3, seems to be an error, the code is written as ( : ) without the spaces.)

PROGRAM p
IMPLICIT NONE
INTEGER, DIMENSION(Smile, ALLOCATABLE :: i
INTEGER :: ios
!
WRITE (UNIT=*,FMT=*) ALLOCATED(i),SIZE(i)
ALLOCATE (i(5),STAT=ios)
WRITE (UNIT=*,FMT=*) ALLOCATED(i),SIZE(i)
DEALLOCATE (i)
WRITE (UNIT=*,FMT=*) ALLOCATED(i),SIZE(i)
!
END PROGRAM p
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PaulLaidler
Site Admin


Joined: 21 Feb 2005
Posts: 7916
Location: Salford, UK

PostPosted: Mon Apr 21, 2008 5:18 pm    Post subject: Reply with quote

The Fortran 95 Standard says that SIZE must not be used when the array has not be allocated. So this is essentially a programming error that is difficult for FTN95 to trap.

When I tested with /checkmate the result was zero but you may not be able depend on this.
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