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Thanks for this... yes, I'll ride the learning curve like a trooper. Checked out that page (same one given earlier I think... great minds think alike!)

my problem was to refer to a as an integer...
i had a=3 and in my equation i used the value 3.

Instead, I just changed that to 3.0 everywhere, and I'm good!

Did a more accurate calculation on the iteration (instead of adding to previous, possibly wonky, value, I RE-calculated).

Thanks for this guys!

Again, another little problem and I hope I'm not embarassing myself here...

Here is the simple code:

real*8 :: a
do i = 1, 2000
if (i>1) then
a= 3 + ((i-1)*((4-3)/1999))
end if
w ...

i declared my a as real*4
and all was going well but...
on the 1924th (or so) iteration of adding 0.00125 to 1.5...

when i would expect the value of 3.90255 to go to 3.90380
it actually jumps to ...

must be a stupid question but...
i have a variable a = 1.5
i add to it 0.00125
and then a shows in a write as 1.50124999997

what am i doing wrong?

is there a different declaration for fixed f ...

i am a novice so i can quite understand why i fell at the first hurdle, but I found your forum and being here is so great of you!
I was using Simply Fortran (just found it first) at first until I had ...

Thank you all so much for helping me out with my novice question! Your help has solved the problem and I'm writing with glee now! Have a great week!

Doing fortran at Uni this year and using the marvellous PLATO to edit,compile, build and run my programs on a windows 10 laptop.

Most things going swimmingly fine with one exception: I can’t work o ...